Michael J. answered • 10/12/15

Effective High School STEM Tutor & CUNY Math Peer Leader

To find the real zeros, set f(x) equal to zero.

0 = x

^{4 }- x^{3}- 20x^{2}Factor out an x

^{2}on the right side of equation. This is the GCF.0 = x

^{2}(x^{2}- x - 20)0 = x

^{2}(x - 5)(x + 4)The zeros are -4, 0, and 5. Since the factor x has an exponent of 2, 0 has a multiplicity of 2 because the factor appears twice. (x - 5) and (x + 4) both have an exponent of 1. These factors appear only once, so -4 and 5 both have a multiplicity of 1.

Tumaiesla G.

10/12/15