Let (4, y) be such a point
So, we want to find y so that the distance from (-4,2) to (4,y) is 10
By the distance formula, √[(4-(-4))2+(y-2)2] = 10
Simplifying, we get: √[64+y2-4y+4] = 10
Square both sides to obtain: y2-4y+68 = 100
y2-4y-32 = 0
(y-8)(y+4) = 0
y = 8 or y = -4
NOTE: Since we squared both sides we need to check both values of y in the original equation to make sure that there are no extraneous solutions. Doing this, we see that both values of y satisfy the original equation.