
Thomas E. answered 10/07/15
Tutor
4.9
(420)
Tom E., a Patient and Knowledgeable Mathematics Tutor for You
Let the fist consecutive number be x, the second one must be x+2 and the third would be x+4. Therefore:
x + (x+2) + (x+4) = 102 and solve for x
3x + 6 = 102
3x = 96
x = 32
The three numbers are 32, 34 and 36.