Michael J. answered 09/28/15
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Effective High School STEM Tutor & CUNY Math Peer Leader
When a diagonal is drawn inside a rectangle, two congruent right triangles are formed. The two legs of the right triangle are the two sides of the rectangle.
Let one side = x
Let the other side = x + 2
Diagonal = 10
Since we have a right triangle, we can use the Pythagorean theorem.
x2 + (x + 2)2 = 102
x2 + (x + 2)(x + 2) = 100
x2 + x2 + 4x + 4 = 100
2x2 + 4x + 4 = 100
2x2 + 4x - 96 = 0
Factor out a 2.
2(x2 + 2x - 48) = 0
Set the term in parenthesis equal to zero.
x2 + 2x - 48 = 0
(x - 6)(x + 8) = 0
x = 6 and x = -8
Since we cannot have a negative dimension, we accept the positive value of x:
x = 6
Plug this value of x into the variables.
One side = 6 meters
The other side = 8 meters
6, 8, and 10 are Pythagorean triples. This verifies we have a right triangle and the side lengths check out.