Ketaki M. answered 09/27/15
Tutor
New to Wyzant
Ketaki M Math,SAT,ACT.GRE,AP CAlculus
let the number of vehicles be 100
then number of vehicles with both expired =2
number of vehicles with expired registration but not expired sticker is 1
and no. of vehicles with exp sticker but not exp registration is 7.
so out of 100 ,no of vehicles having atleast one of these is 2+1+7=10
hence number of vehicles having none of the above is 90
hence required probability is 90/100 ie 9/10