Thomas E. answered 09/24/15
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Allow J=Jason, D=Darcy and M=Maria. We need to set up a series of equations:
J-29 = D (Jason has 29 more dollars than Darcy)
M = 2J (Marcy has twice as much as Jason)
J + D + M = 268 (they share 268 dollars
This provides a system of 3 equations in s 3 variables. The easiest way to solve this is to substitue the values of D and M (in terms of J) from the first 2 equations into the third:
J + (J-29) + (2J) = 268 and solve with algebra
4J = 297
J= 297/4 = 74.25 substitute this for J in the first 2 equations
D=74.25 - 29 = 45.25
M = 2(74.25) = 148.50
Therefore Darcy and Jason have 74.25+45.25 = 119.50