Search 85,330 tutors
FIND TUTORS
Ask a question
0 0

(t+7)^2 . t+5 over (t+5)^2 . t-1

Tutors, please sign in to answer this question.

1 Answer

What you did is not correct,
 
Is it ( 7 + t)(t+5) / ( t + 5 )2 ( t -1 )
 
      ( t + 7 )2 / t+ 4t -5
 
           ( t+ 7 ) 2/ ( t+5)(t - 1 ):
 
  May be it was:
   
  ( t + 7) ( t + 5 )2 / ( t +5 )( t -1 )= 
   
   ( t +7 ) ( t +5 ) / ( t -1 )