
Russell G. answered 09/27/15
Tutor
New to Wyzant
Business Tools for Success
We know rate * time = distance
So if t1 is the time of the initial run,
and t2 is the time of the faster run:
7t1 = d1 (d1 being distance ran at first speed)
And (7.8)t2 = d2 (d2 being the distance ran at second speed)
So if total distance is 26 miles,
So if total distance is 26 miles,
and total time is 3.5 hours, then we know:
(formula 1) d1 + d2 =26
(formula 2) t1 + t2 = 3.5
Substituting rate * time for the distances d1 and d2 of formula 1, we get:
(formula 3) 7t1 + (7.8)t2 = 26
As we learned in Algebra, if we have two formulas with the same variables, we can find the place where both are true. We do this by combining the formulas to eliminate the extra variable and solve the problem:
In this set, we can do that easily by multiply both sides of formula 2 by -7
formula 2 : t1 + t2 = 3.5
formula 2 * -7 : -7(t1 + t2) = -7 (3.5)
formula 2 * -7 : -7(t1 + t2) = -7 (3.5)
-7t1 -7t2 = -24.5 (new formula 2)
7t1 + (7.8)t2 = 26 (formula 3)
Combining these (adding them together) the t1 values go away, and I can solve a single variable equation easily.
.8t2 = 1.5
t2 = 1.5 / .8
t2 = 1.875 hours
So if t1 + t2 = 3.5, then
So if t1 + t2 = 3.5, then
t1 = 3.5 - 1.875
t1 = 1.625
And distance is
d2 = 7.8 * 1.875 = 14.625 miles
d1 - 7 * 1.625 = 11.375 miles
Proof :
Proof :
d1 + d2 = 26
11.375 + 14.625 = 26 Check!
t1 + t2 = 3.5
1.625 + 1.875 = 3.5 Check!
t1 + t2 = 3.5
1.625 + 1.875 = 3.5 Check!
(I did this with combining formulae for two reasons: 1 - good to remind you that the things you learned previously are not dead ends but doorways! And 2 - the math of combining the numbers was easier! :)