The length of a rectangle exceeds twice its width by 1 inch. The perimeter of the rectangle is 32 inches. find the length and width.

Question

SET UP AND SOLVE WORD PROBLEM:

Answer 1

If w is the width, then the length is 2w +1

 

The peremeter = 2( 2w+1 + w)

 

Thus, 2( 2w+1 + w) =32

 

2(3w+1)= 32

 

3w+1 =16

3w =15  therefore w= 5 inch  and  length= 2x5+1 =11 inches