a shuttle is in rest and accelerates to velocity of 12300m/s in 1st few min. if it holds an acceleration of 29.4m/s^2 for 1st few min, how far does it travel?

Question

This is a Physics 1D Kinematics question 

Answer 1

v_i= 0 m/s

v_f= 12300 m/s

a = 29.4 m/s²

Δx = ?

Kinematic Equation: Δv²=2aΔx

v_f²=v_i²+2aΔx

(12300 m/s)²=(0 m/s)²+2(29.4 m/s²)Δx

When initial velocity is 0 m/s, v_f²/2a=Δx

Δx=2.57x10⁶ m