
David W. answered 09/19/15
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Let's assume that the road is a safe D-I-R-T (Distance-Is-Rate-times-Time) road. Usually, with such problems, two of the variables are related or else they are constant. In this problem the Distance is the same for the turtle and the rabbit.
The problem also wants to know the difference of their distances when the rabbit crosses the finish line (and wins), so we will need to find its race time so we can determine the position of the rabbit (unless, of course, the turtle wins and we have to determine the location of the rabbit).
O.K. how long does the rabbit take to run the race? D=RT so T=D/R
TR = (3 km)/(5 m/s) + (5 min head start)
TR = (3 km) (1000 m / km) / (5 m/s) + (5 min)(60 sec / min)
TR = 600 + 300 s
TR = 900 sec (that's 15 minutes)
Now, how long does it take the turtle? to run the race
TT = (3 km) ( 1000 m / km) / (1 m/s)
TT = 3000 sec (oh, that's 50 minutes -- it lost)
And, where was the turtle when the rabbit won?
Well, in just 15 min (the rabbit's winning time) on the road, the turtle traveled (remember: D=RT):
DT = (1 m/s)(900 s)
DT = 900 m
That means the rabbit finished the 3 km (that is, 3000 m) course when the turtle was at meter marker (similar to highway mile markers) 900. Ouch! that's winning by 2100 m.