James B. answered • 09/10/15
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Ignore the 12m. You have two triangles, both of them have a height of 10m and a base of 6m. The wire is the hypotenuse of the triangle.
Lw = Length of Wire for the stay
Lw = sqrt(10m*10m + 6m*6m) = sqrt(100+36) = sqrt(136) ≈ 11.66m of wire
For both stays you'll need twice that amount: 23.32m
They only have 1.53m of wire (153cm * 1m / 100cm). So they don't have enough.
James B.
It could be I misunderstood the problem. I was assuming they were attaching a wire 10m up the mast and bringing it down to the ground 6m away from the mast. But reading it again, I can see where they might mean they're attaching the wire to the top of the mast and running it to a point that's 10m in the air (a wall, another pole, etc) that's 6m from the mast. So the triangle now becomes 2m drop and 6m run.
But that gives an even smaller amount that's required (1265cm).
So I can't imagine how they got that number.
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09/10/15
Emily D.
09/10/15