Arthur D. answered 09/09/15
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f(x)=x^3+8 is the sum of two cubes
x^3+2^3=0
the general rule for factoring the sum of two cubes is a^3+b^3=(a+b)(a^2-ab+b^2)
using the rule...
(x+2)(x^2-2x+4)=0
x+2=0
x=-2 is one root
x^2-2x+4
use the quadratic formula
[2±√4-16]/2
[2±√-12]/2
[2±2√3√-1]/2
[2±2i√3]/2 (i=√-1)
1±i√3 are the other two roots (1+i√3 and 1-i√3)
now you have the three zeroes or roots