Jordan K. answered 09/08/15
Tutor
4.9
(79)
Nationally Certified Math Teacher (grades 6 through 12)
Hi Bianca,
Let's begin by seeing whose charge is greater for a 1 hour mowing job:
David's mowing charge: $15 + $5.50(1) = $20.50
Ari's mowing charge: $12 + 6.25(1) = $18.25
We can see that initially, David's mowing charge will be greater than Ari's mowing charge.
To find out how big a mowing job (in hours) it will take for Ari's mowing charge to equal David's mowing charge, we can set up expressions in terms of x hours to represent each of their mowing charges. Then we will set them equal to each other and solve for x (number of hours it takes for them to charge the same amount):
David's mowing charge: 15 + 5.50x
Ari's mowing charge: 12 + 6.25x
15 + 5.50x = 12 + 6.25x (equal mowing charges)
6.25x - 5.50x = 15 - 12
0.75x = 3
x = 3 / 0.75
x = 4 hours (equal mowing charges)
x > 4 hours (Ari charges more)
So we see it will take at least a 4 hour mowing job for Ari's mowing charge to catch up with David's mowing charge and that a mowing job greater than 4 hours will have Ari's mowing charge surpass David's.
Thanks for submitting this problem and glad to help.
God bless, Jordan.