An automobile with an initial velocity of 4.30 m/s accelerates uniformly at the rate of 3.00 m/s^2. Find the final velocity and the displacement after 5.00 s.

v(t)=v

_{0}+a*tSo v(5)=4.3+3*5=19.3 m/s

d(t)=v

_{0}*t+a*t^{2}/2d(5)=4.3*5+3*5

^{2}/2=21.5+37.5=49 m
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