Find the final velocity?

Question

 

An automobile with an initial velocity of 4.30 m/s accelerates uniformly at the rate of 3.00 m/s^2. Find the final velocity and the displacement after 5.00 s.

Answer 1

 

Hello again, Sun -- here's the "play-by-play" ... the speed stair-steps 4.3, 7.3, 10.3, 13.3, 16.3, 19.3m/s at 5sec ... ave speed is 11.8 m/s running for 5 sec ==> displaces 55 +4 or 59m :)

Answer 2

v(t)=v₀+a*t

So v(5)=4.3+3*5=19.3 m/s

 

d(t)=v₀*t+a*t²/2

 

d(5)=4.3*5+3*5²/2=21.5+37.5=49 m

Answer 3

V = Vo + at = 4.30 + 3.00*5.00 = 19.30 m/s

d = Vot + (1/2)at^2 = 4.30*5.00 + (1/2)(3.00)(5.00)^2 = 59.00 m

or

d = (1/2)(Vo+V)t = (1/2)(4.30+19.30)(5.00) = 59.00 m