A can of tuna is dropped from a building. If the can takes 3.2 seconds to strike the ground, what distance did it fall?

d = (1/2)gt^2 = 4.9*3.2^2 = 50.2 m <==Answer

Tutors, please sign in to answer this question.

Scottsdale, AZ

d = (1/2)gt^2 = 4.9*3.2^2 = 50.2 m <==Answer

East Setauket, NY

When solving any problem of this type it is helpful to use the following problem solving steps.

V_{i} (initial velocity) = 0

t (time) = 3.2s

d = variable we are solving for

a (acceleration) = 9.8 m/s^{2}

The correct formula will contain the known variables and only one unknown, which will be the variable we are solving for (d).

The correct formula is d = v_{i}*t+1/2 at^{2}^{ }because v_{i}=0, which makes the v_{0}*t term drop out, leaving us with d=1/2at^{2}

d = 1/2*9.8*3.2^{2}

The answer is 50.2m

El Paso, TX

The equation for this is d=(gt^{2})/2.

d= Distance

g= Gravitation Acceleration (which for earth is 9.807m/s/s)

t = Time

Then

d=(9.807*3.2^{2})/2

Then it simplifies to:

d=50.210048

Blacksburg, VA

Hey Sun -- 3.2s freefall gives Vf of 32m/s ... ave speed of 16m/s runs 3.2s

==> falls about 50m :)