A truck falls off a cliff. If the cliff is 33.5 m high, how much time for the truck to reach the bottom?

h = (1/2)gt^2

Solve for t,

t = sqrt(2h/g) = sqrt(2*33.5/9.8) = 2.6 sec <==answer

Tutors, please sign in to answer this question.

Scottsdale, AZ

h = (1/2)gt^2

Solve for t,

t = sqrt(2h/g) = sqrt(2*33.5/9.8) = 2.6 sec <==answer

Blacksburg, VA

Sun -- you may like KE=PE ... 0.5mv*v = mgh ... Vf= sqrt(2gh) = sqrt 670 ~ 26m/s

==> takes 2.6s from rest ... Best wishes, sir :)

El Paso, TX

The equation for this is t=sqrt(2d/g).

t= Time

d= Distance

g= Gravitational Acceleration (~9.8 m/s/s)

The equation would be:

t=sqrt(2*33.5/9.8)

Simplified it becomes:

t= 2.61382834688