A truck falls off a cliff. If the cliff is 33.5 m high, how much time for the truck to reach the bottom? 9/4/2013 | Sun from Los Angeles, CA | 3 Answers | 0 Votes Mark favorite Subscribe Comment
h = (1/2)gt^2 Solve for t, t = sqrt(2h/g) = sqrt(2*33.5/9.8) = 2.6 sec <==answer 9/4/2013 | Robert J. Best answer Comment
Sun -- you may like KE=PE ... 0.5mv*v = mgh ... Vf= sqrt(2gh) = sqrt 670 ~ 26m/s ==> takes 2.6s from rest ... Best wishes, sir :) 9/6/2013 | Brad M. Comment
The equation for this is t=sqrt(2d/g). t= Time d= Distance g= Gravitational Acceleration (~9.8 m/s/s) The equation would be: t=sqrt(2*33.5/9.8) Simplified it becomes: t= 2.61382834688 9/4/2013 | Brice B. Comment