A ball is thrown down off the cliff at 12 m/s. How fast is it going 3.5 s later?

12m/s + (3.5s)(9.8m/s

^{2}) = 46.3m/s-
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A ball is thrown down off the cliff at 12 m/s. How fast is it going 3.5 s later?

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12m/s + (3.5s)(9.8m/s^{2}) = 46.3m/s

We know: Vinitial, acceleration, and time.

We want to find: Vfinal.

Equation containing these variables of interest: Vfinal - Vinitial=axt

Plug and Chug!

Vfinal=Vinitial +axt

Vfinal= 12 + 9.8x3.5= 46.3 m/s

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