what is 4 squared -8*6/4+7+ (3 to the power of 4)

Question

this is something I made up to help me with my orders of operations can you help me explain it to myself

Answer 1

Is this your original problem? 4²-8*6/4+7+3⁴

 

you need to use order of operations (PEMDAS)

 

4²-8*6/4+7+3⁴        simplify exponents

16-8*6/4+7+81        Preform multiplication and division

16-48/4+7+81

16-12+7+81             Preform Addition and subtraction

4+7+81

13+81

94

 

94 is your final answer

Answer 2

This is a great example of using the order of operations for solving equations. Remember that the order of operations states that multiplication and division are solved for first then addition and subtraction are solved for. So rewritten your equation will look like this:

 

4^2-((8*6)/4)+7+(3^4); solve multiplication you get 8*6=48; then division 48/4= 12

 

such that  4^2-(48/4)+7+(3^4) = (4^2)-(12)+7+(3^4)= 16-(12)+7+81; what's left is simple addition and subtraction.

 

OR 

 

16-12+7+81= 92