(x-7)/(x+8) ≤ 0
x - 7 = 0 when x = 7
x + 8 = 0 when x = -8
When x < -8, x - 7 < 0 and x + 8 < 0. So, (x-7)/(x+8) > 0
When -8 < x < 7, x - 7 < 0 and x + 8 > 0. So, (x-7)/(x+8) < 0
When x > 7, x - 7 and x + 8 are both positive. So, (x-7)/(x+8) > 0
(x-7)/(x+8) = 0 when x = 7 and (x-7)/(x+8) is undefined when x = -8
Solution: -8 < x ≤ 7 Interval notation form: (-8, 7]