
Andrew M. answered 09/03/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Let N = # minutes Nancy has
W = # minutes Warren has
C = # minutes Christen has
M = # minutes Megan has
W = (N+20)/4 20 more than Nancy, divided by 4
C = (3N-50)/2 3 times Nancy, - 50, total divided by 2
M = (5(N-20))/4 5 times the difference of Nancy and 20, quantity divided by 4
N + W + C + M = 195 total minutes for all 4 is 195
Replace each variable W, C, M with the equivalent expression
N + (N+20)/4 + (3N-50)/2 + (5(N-20))/4 = 195
To get rid of the fraction multiply everything through by 4
4N + (N+20) + 2(3N-50) + 5(N-20) = 4(195)
4N + N + 20 + 6N - 100 + 5N - 100 = 780
16N -180 = 780
16N - 960
N = 960/16 = 60 mins
W = (N+20)/4 = 80/4 = 20 mins
C = (3N-50)/2 = 130/2 = 65 mins
M = 5(N-20)/4 = 200/4 = 50 mins
Nancy has 60 mins
Warren has 20 mins
Christen has 65 mins
Megan has 50 mins
Total: 195 mins