Arthur D. answered 08/30/15
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3=(r-1)t
3=(r+1)(4-t)
from the first equation, t=3/(r-1)
substitute into the second equation
3=(r+1)(4-[3/(r-1)])
3=(r+1)([4(r-1)-3]/(r-1))
multiply both sides by (r-1)
3(r-1)=(r+1)(4[r-1]-3)
3(r-1)=(r+1)(4r-4-3)
3(r-1)=(r+1)(4r-7)
3r-3=4r^2+4r-7r-7
3r-3=4r^2-3r-7
4r^2-3r-7-3r+3=0
4r^2-6r-4=0
divide both sides by 2
2r^2-3r-2=0
factor
(2r+1)(r-2)=0
r-2=0
r=2 mph is the rate of the canoe