Debbie O.

asked • 08/28/15

Travel by a slow and faster train to same destination

An express train takes 51/2 hours to travel between two cities. If the Express train takes only 3/5 of the time an ordinary train takes, how long will it take for the ordinary train to travel between the two towns?
Thank you for the answer Bob, but how do I set this out as a 'Let' statement?

Debbie O.

Thank you for your answer Bob :) How would I set this out answering as a 'let' statement?
Report

08/28/15

Bob P.

tutor
Debbie,
I suppose you are looking for something like this...
Let X = the time an ordinary train takes to travel between the two towns.
Then 5.5 hours = 330 minutes = (3/5) X
Solve for X
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08/28/15

Debbie O.

Thank you for trying Bob, but I have no idea how to set this out as an algebraic equation and then solve. I'm having so much trouble with this module :/......Thanks anyway
Report

08/30/15

Bob P.

tutor
Let X = the time an ordinary train takes to travel between the two towns.
Let Y = the time an express train takes to travel between the two towns.
The Express train takes only 3/5 of the time an ordinary train takes,
so Y = (3/5) X.
You are given the time an express train (Y) takes to travel between two cities (5.5 hours), and are asked (to solve for) how long will it take for the ordinary train to travel between the same two cities.
 
Y = 5.5 hours = 330 minutes
Y = (3/5) X
330 minutes = (3/5) X
Solve for X by multiplying both sides of the equation by (5/3)
(5/3) * 330 minutes = (5/3) * (3/5) X
550 minutes = (15/15) X = X
X  = 550 minutes = 9 hours 10 minutes
 
You can check the answer you got for X by plugging it back into the original information:
The Express train takes only 3/5 of the time an ordinary train takes.
Y = (3/5) X
330 minutes = (3/5) 550 minutes
330 minutes  = 330 minutes 
 
Does that help?
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08/30/15

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