Mark M. answered 08/17/15
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Retired math prof. Very extensive Precalculus tutoring experience.
The common denominator is (1-cosx)(1+cosx) = 1-cos2x
So, 1/(1-cosx) - 1/(1+cosx) = (1+cosx)/(1-cos2x) - (1-cosx)/(1-cos2x)
= 2cosx/(1-cos2x)
= 2cosx/sin2x = 2(cosx/sinx)(1/sinx)
= 2(cotx)(cscx)
Mark M.
08/17/15