
John C. answered 08/02/15
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7 - 2/b < 5/b First, to make our lives easier, lets multiply everything by b.
7b - 2 < 5 Then we move the 2 over
7b < 7 Then we divide both sides by 7
b < 1 Answer. lets check. if we plug in a number less than b, the equation should still be correct. let's try b = 1/2
7 -2/(1/2) < 5/(1/2)
7 -4 < 10
3 < 10 this equation is still correct. so we know that value of b works. we know for a fact that b is less than 1. however we don't know what it's minimum is. we know that zero doesn't work since 2/0 and 5/0 are both impossible. what about negative numbers? lets try b = -1
7 - 2/(-1) < 5/(-1)
7 +2 < -5
9 < -5 this is not true. if you keep trying all negative numbers don't work. even negative fractions don't work. That said. we can conclude that b has the domain (0,1). Meaning that b can be anywhere number between 0 and 1.
Hope that helps. Let me know if you have any questions.
John