
Andrew M. answered 07/28/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
f(x)=x+2 g(x)=x+5
(f+g)(x)= f(x)+g(x) = (x+2) + (x+5) = 2x+7
(f-g)(x)=f(x)-g(x)= (x+2)-(x+5)=x+2-x-5=-3
(fg)(x)=(f(x))(g(x))= (x+2)(x+5)=x2+5x+2x+10
= x2+7x+10
(f/g)(x)=f(x)/g(x)= (x+2)/(x+5)