Yanping S. answered 07/11/15
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I break down abstruse math/science concepts into easy-to-digest pieces
To explain it in more clearer, concise terms, a soldier needs to eat a certain amount of rice per day. Thus each soldier has a food consumption *rate* R. This is a time rate, normalized to one soldier.
Even if you have more soldiers, this per-soldier food consumption rate *doesn't change*. This rate is thus defined:
R = food / (days * soldiers)
This R is a RATE CONSTANT defined by the problem. We can solve for it by realizing that
R = 20 tonnes / (300 days * 72 soldiers)
If we calculate this out we get 9.26 * 10^-4 or 1/1080. You can easily confirm this by taking the inverse of R (that is, 1/R) which is (300 days * 72 soldiers) / 20 tonnes and finding that it is 1080 "soldier*days per ton".
Thus 1/R = 1080 soldier*days / ton
It is looking at the inverse of R -- 1/R -- that allows us to solve the problem.
If you multiply 1/R by 32 tons, you get the amount of soldier*days worth of food consumption that 32 tons of rice will give you.
Thus 1/R * 32 tons = 32 tons / R = 32 * 1080 soldier days = 34560 soldier days
Then divide this number of soldier days by the number of solders (540)
Thus we have the equation
1/R * 32 tons / 540 days = 1080 (soldier * days / ton) * 32 tons / 540 soldiers
The units cancel, getting us 64 days.
Yanping S.
I'm approaching it from a STEM standpoint. In a problem, you always have to figure out what is constant, what is variable, and assign names to those constants and variables to keep yourself from getting confused.
Yes, not doing this might not be important for a fifth-grade ratio problem, but as the problems get harder and harder, grounding young kids in the fundamentals of physics at a young age is important, especially when you get to the beauty of equations like PV = nRT
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07/11/15
Andrew M.
07/11/15