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Question

Rectangle A has a length of 5 inches and a width of 3 inches. Rectangle A has the same area as Rectangle B, but has different dimensions. The width of Rectangle B is 50% shorter than the width of Rectangle A as shown.



Which percent represents how much longer the length of Rectangle B must be to maintain the same area as Rectangle A?


It must be 3% longer than Rectangle A.


It must be 6% longer than Rectangle A.


It must be 50% longer than Rectangle A.


It must be 100% longer than Rectangle A.

Answer 1

Rectangle A:

 

length = 5 in

width = 3 in

Area = 15 in²

 

 

Rectangle B:

 

width = 3 - 3(0.5) = 1.5 in

Area = 15 in²

 

 

length = Area / width

          = 15 in² / 1.5 in

          = 10 in

 

Compare the two lengths, 5 in  and  10 in.

  

5 + 5r = 10

      5r = 5

        r = 1

 

Multiply the value of r by 100 since r is in decimal form.

 

It must be 100% longer than rectangle A.

 

 

 

 

Answer 2

100% since that represents twice or double