Vishal V.

asked • 07/02/15

sets problems

in a school 120 students are participating in game A or game B or both. if students are participating in game A is 50% and 30% to 60% of these students are participating in both A and B . what % of the students are participating only in A.
 
(a)20%
(b)40%
(c)25%
(d)30%
(e)50%

2 Answers By Expert Tutors

By:

David W. answered • 07/02/15

Tutor
4.7 (90)

Experienced Prof

Rizwan S.

Thanks for your input. It certainly clarifies some logic with the 30-60 range!
But even so, why can't the answer be (a) 20%?
 
If 20% are in A, that is 24 students, leaving 36 in A&B (and 60 in B).
Similarly, we could consider 30% in A (as you say) which would simply reverse the numbers in A and A&B. Also adds up.
And even further, we could consider (c) 25% with 30 in A, 30 in A&B and 60 in B.
 
How would you justify 30% as the definitive answer?
Report

07/02/15

David W.

Sorry, I made the mistake of editing my answer and this software reverted to my unchanged answer, so now I'm re-editing everything in MS Word;  I'll respond again (and change my answer) in a few minutes.
Report

07/02/15

Rizwan S.

Thanks for the update.
 
However, the question remains, why can't (a) 20% (24 students in A) be an option? You say "60% is not allowed" but the question explicitly states 30 to 60% (of those in A) can be in B as well, i.e. A&B.
 
I continue to argue in support of (a):
 
50% (60 students) play A
30-60% of these (18-36 students) also play B
 
Given your table, 36 is certainly an acceptable number for A&B leaving 24 (i.e. 20%) in A alone.
 
However - a similar argument can be made for (c) 25% and (d) 30%.
 
I therefore contend that either the answer is (a) 20% since this will necessarily be true (there will be at least 24 students in A alone and as many as 42) OR there is more to the question/the wording is slightly off.
Report

07/02/15

David W.

Aha, you quick comments hit my revisions mid-stream again (I had to log off and back on to get updated Answer, thus REVISED again).
 
So, (a), (c), or (d)  ..... ??
 
 "At least" is a necessary amount (you're even more tricky than this question), but not sufficient to count other answers wrong.
Report

07/02/15

Rizwan S.

Yes, I agree we cannot reduce (c) and (d) for sure since they do seem to meet the requirement.
 
I would wait to hear back from OP - perhaps he made a mistake in communicating the question!
Report

07/02/15

Rizwan S. answered • 07/02/15

Tutor
5.0 (21)

Math, Economics, SAT & Public Speaking Tutor

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.