F=qvXB. Since the field is already perpendicular to the velocity, the formula is just qvb. If the charge quadruples and the speed doubles, the force will be 8 times as great (4q*2v*B=8qvb)
Charles W.
asked • 06/11/15Help me with this question
A charged particle a moves with velocity v in a magnetic field B that perpendicular to each other.The particle experiences Lorentz Force of F.If another particle of 4q moves twice faster in similar field,then how strong of Lorentz force is the second particle experienced?
A.2
B.4
C.6
D.8
E.10
A.2
B.4
C.6
D.8
E.10
Follow
•
2
Add comment
More
Report
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
