find the slop, y, and the y intercept 4y+3x=12

Question

find the slop, y, and the y intercept

Answer 1

Hi! If I understand correctly you are looking for the slope, y-equation, and y-intercept of this equation.

 

If you are to rearrange this equation to see the answer more clearly here are the steps:

1. First subtract 3x from both sides of the equation

 

4y+3x-3x = 12 - 3x   =>   4y = 12 - 3x

 

2. Next divide both sides by 4 in order to get the equation in terms of y

 

(4y)/4 = (12 - 3x) / 4   =>   y = 12/4 - (3/4)x

this simplifies to y = 3 - (3/4)x

 

In this form the slope is indicated by the coefficient of the x value (don't forget the negative sign!), which in this case is:

 

-(3/4)

 

The y-intercept is the remaining number which is:

 

3

 

To clarify:

 

slope => -(3/4)x

(remember that a negative slope means the y values are decreasing as the x values increase)

y-intercept => 3

(where the line crosses the y-axis)

y-equation (simplified) => y = 3 - (3/4)x

Answer 2

The equation of any line is in the form  y=mx+b, where m is slope and b is y-intercept.

 

We must get the given equation in this form.

 

 

Subtract 3x on both sides of equation.

 

4y = -3x + 12

 

 

Divide both sides of equation by 4.

 

y = -(3/4)x + 3

 

 

The slope is -3/4

The y-intercept is 3