
Mark M. answered 06/09/15
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
53.
(e2)3x = (e2x)(e3x)
e6x = e5x
6x = 5x
x = 0
54.
3lnx - ln(x3 - 2x + 4)
lnx3 - ln(x3 - 2x + 4)
ln[ x3 / (x3 - 2x + 4)
A law:
eln a = a
e raised the the expression above results in x3 / (x3 - 2x + 4)
55.
From where did you get this one?
56.
Argument for first "ln" is missing.