Juliet T. answered 06/09/15
Tutor
New to Wyzant
Certified Singapore PreK-12 Math Teacher, over 20 years of experience
Hi Max, I'm not sure if you still need help since your question was posted quite some time back. Anyway, hope the following helps.
Concepts that you need to know:
1) The function given is Q(t), which means Q is given in terms of t. Inverse of the function needs you to give t in terms of Q, which is the reverse way. So, your aim is to make t the subject of the given formula.
2) When ex = y, x = ln y where y > 0.
3) 90% = 0.9, maximum capacity is Q0. I believe (b) is referring to charging it to 90% of MAXIMUM capacity. So, this means that the question wants you to solve for t when Q(t) = 0.9Q0.
Solution:
(a)
Q = Q0(1 - e-t/a)
Q/Q0 = 1 - e-t/a
e-t/a = 1 - Q/Q0
-t/a = ln(1 - Q/Q0)
t = (-a) ln(1 - Q/Q0)
t = (-a) ln(1 - Q/Q0) tells us the time taken in seconds to recharge the flash's capacitor till it stores electric charge Q after the camera flash goes off.
(b)
Note: Since the question did not restrict us to using answer from (a) to do (b), we can use the given formula Q = Q0(1 - e-t/a) to solve part (b). You may prefer to do it in this manner, just in case your answer to part (a) is wrong. Alternatively, we can use answer from part (a), which will be a more direct method since we are trying to find the time taken for the recharging process. Anyway, both works fine by substituting Q = 0.9Q0 and a = 2. You can use both to check your answer.
I will use part (a) answer to solve this.
t = (-a) ln(1 - Q/Q0)
= (-2) ln(1 - 0.9Q0/Q0)
= (-2) ln(0.1)
= 4.61 (rounded off to 3 s.f.)
In conclusion, it takes 4.61 s to recharge the capacitor to 90% of capacity if a=2.