When you factor things, you are probably used to seeing something like X^{2 }+ BX + C = (X+ )(X+ ), where the two numbers that go in the blanks add up to B and multiply to C. In this case, we can think of the equation as 3X^{2 }+ 0X + 0. Now, we factor out the 3, and get 3(X^{2} + 0X + 0). Now we use the parentheses.
3(X+ )(X+ ) we are looking for two numbers that add up to 0 and multiply to 0. What are they? 0 and 0 of course! So,
3(X+0)(X+0) is the factoring. Since X+0 just equals 0, our final answer is
3(X)(X).
This may look like there are a few extra steps, but if you always do these problems in the same way, they will become much easier.
6/28/2013

Yitzhak S.