Andrew D. answered 05/26/15
Tutor
5
(15)
Harvard Grad offers Test Preparation and Tutoring
3cos 2x - 4cos^2 x +2= 0
There is a formula for cos2x=2cos^2x-1 (=1-2sin^2x)
Substituting for cos2x:
3(2cos^2x-1))-4cos^2x+2=0
2cos^2x-1=0
solve as in part b) of your previous question