Inactive Tutor answered 05/25/15
Tutor
New to Wyzant
Lindsay,
Here's a simple geometric proof:. Please draw the diagram:
Start with an equilateral triangle ABC with apex at A. Each of its angles is 60 degrees. Let each side measure x.
Take the perpendicular from A meeting BC at D. By RHS, the two triangles ABD and ACD
are congruent and therefore AD bisects angle A and the side BC. So angle BAD is 30 degrees and side BD is x/2
BD/AB=(x/2)/x=1/2 is the definition of sine BAD =sine 60/2 =sine 30
QED
It is interesting to note that the sine of some angles can be expressed as fractions, some with radicals but most are transcendental....As Andrew M points out. sine can take on any value from -1 to +1. It is only the sine of special angles that are not transcendental..30, 60 , 45 and 90 degrees are well known to you and generally you will memorize. It was a big question hundreds of years ago which angles could be constructed with ruler and compass and this geometric question is highly related to the question of which sines are not transcendental.