We start by identifying the stoichiometric equation for the reaction.
NaCl + AgNO3 ---> AgCl + NaNO3
This equation is already balanced, but always be sure to check!
Next we need to convert the mass of our NaCl into moles.
34.19 g NaCl * (1 mol NaCl / 58.44 g NaCl) = 0.585 mol NaCl
Since sodium chloride is the limiting reagent, this is the maximum number of moles available in the reaction. Convert to moles of silver chloride.
0.585 mol NaCl * (1 mol AgCl / 1 mol NaCl) = 0.585 mol AgCl <--- This conversion factor comes from the stoichiometry
Then convert from moles of silver chloride to grams of silver chloride.
0.585 mol AgCl * (143.32 g AgCl / 1 mol AgCl) = 83.85 g AgCl
Therefore the total amount of silver chloride we can produce is 83.85 g.