Yohan C. answered • 05/21/15
Tutor
4
(1)
Math Tutor (up to Calculus) (not Statistics and Finite)
Hi Emily,
First, you have to look at the equation and take partial derivatives to each variable.
For example:
f(x,y) = (-x2/2) -y2 + 25/8
fx (x,y) = -x (because every other variable other than x is constant)
fy (x,y) = -2y (because every other variable other than y is constant)
After finding the partial derivative (slope), put the respected value (point) into the fx (x,y) for slope in x-direction and fy (x,y) for slope in y-direction.
After getting the slope, you can use point-slope equation (x - x1) m = (y - y1) to both. Whatever the "point" (x1, y1, z1) is, use that point (x1, y1, z1) after taking partial derivative to find the equation of its (x value for x-direction and y value for y-direction) tangent lines.
I hope you understand this.
Good luck to you.
Yohan C.
It looks like hx(3,2) and hy(3,2) are the partial derivatives of h(x,y) to each variable (x,y) and (3,2) are the points for each x and y to find the slope of the tangent line to each direction. For x-direction, you put 3 into the hx equation and 2 into hy equation to find out slope of those tangent lines
h(x,y) -> h(4,1) hmmm. You need an original h(x,y) equation to find out the equation of those tangent lines. That way, you can take partial derivative.
Report
05/21/15
Emily P.
05/21/15