Stephanie M. answered 05/13/15
Tutor
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Degree in Math with 5+ Years of Tutoring Experience
I think you meant f(x) = 11x2 + 5x. Let's find its derivative:
f'(x) = 2(11)x + 5
f'(x) = 22x + 5
At x = 9, that's:
f'(9) = 22(9) + 5
f'(9) = 198 + 5
f'(9) = 203
We can re-write f(x) = 3/x as f(x) = 3x-1. That's because a-n = 1/an. Let's find its derivative:
f'(x) = -1(3x-2)
f'(x) = -3x-2
f'(x) = -3/x2
At x = 1, that's:
f'(1) = -3/12
f'(1) = -3/1
f'(1) = -3
The derivative of s(t) is:
s'(t) = 0 - 2
s'(t) = -2
At t = 6, that's just:
s'(6) = -2