Mark M. answered • 05/11/15
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Mathematics Teacher - NCLB Highly Qualified
√(6x + 7) = √(7x + 7) only if x = 0! If x > 0 √(6x + 7) is always < √(7x + 7).
Therefore √(6x + 7) = √(7x + 7) + 6 has not solution.
Please rewrite.
Mark M.
Subtract 8 from both sides
Square both sides
Set quadratic trinomial = 0
Solve
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05/11/15
Josh F.
In question a you put the first +7 under radical can you redo please?
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05/11/15
Josh F.
I got an answer of x=6
correct?
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05/11/15
Josh F.
Never mind I know it's correct
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05/11/15
Mark M.
√(6x) + 7 = √(7x + 7) + 6
√6x = √(7x + 7) - 1
6x = (7x + 7) - 2√(7x + 7) + 1
-x - 8 = -2√(7x + 7)
x + 8 = 2√7x + 7)
x2 + 16x + 64 = 4(7x + 7)
x2 + 16x + 64 = 28x + 28
x2 - 12x + 36 = 0
(x - 6)2 = 0
{6}
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05/11/15
Josh F.
05/11/15