Stephanie M. answered 05/02/15
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Treat the bronze bushing as a composite shape. It's one empty cylinder inside of a full cylinder, neither of which has top or bottom bases. This is how we'll take the wall thickness into account: We'll calculate the volume of a cylinder with diameter 1.9 inches, then subtract the volume of a cylinder with diameter 1.9 - 2(0.35) = 1.9 - 0.7 = 1.2 inches. That smaller cylinder is the amount of empty space there is inside the bushing, since I subtracted the wall's thickness on either side of the diameter.
Large cylinder with d = 1.9:
VL = πr2h
VL = π(0.95)2(2.75)
VL = π(0.9025)(2.75)
VL ≈ 2.4819π in3
Small cylinder with d = 1.2:
VS = πr2h
VS = π(0.6)2(2.75)
VS = π(0.36)(2.75)
VS = 0.99π in3
VS = π(0.6)2(2.75)
VS = π(0.36)(2.75)
VS = 0.99π in3
Volume of bronze bushing:
VL - VS = 2.4819π - 0.99π = 1.4919π ≈ 4.6869 in3
That means 4.6869 cubic inches of bronze weighs 1.50 pounds. That's 1.5 lbs. / 4.6869 in3 = 0.320 pounds for one cubic inch of bronze.