Square roots

Question

3tan^2x-2=csc^2x-cot^2x

0<x<Pi 

Answer 1

3tan² - 2 = csc² - cot²

3tan² - 2 = 1/sin² - cos²/sin²

3tan² - 2 = (1 - cos²)/sin²

3tan² - 2 = sin² / sin²

3tan² - 2 = 1

3tan² = 3

tan² = 1

tan = 1

 

x ∈ {π/4, 5π/4}