Stephanie M. answered 04/29/15
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I think this is a valid way to do this problem, but I'm not 100% sure. Since it hasn't been answered yet, I figured I'd give you my thoughts:
Since there are 2 possible answers for each of the 15 questions, there are 215 = 32768 ways to answer all the questions on the quiz.
Let's figure out how many ways there are to answer at least 12 questions correctly. To pass, the student can answer three questions however he wants, but must answer the other 12 correctly. So, he has 2 answer choices for 3 questions, but only 1 answer choice for the other 12. First, let's find out how many ways there are to choose those 12 correct answers:
"15 choose 12" = 15C12 = 15!/(12!×3!) = (15×14×13)/(6) = 455 combinations of 12 correct answers
Now, for any combination of correct answers, the other three questions on the quiz can be answered either correctly or incorrectly. That's a total of 23 = 8 ways to answer the other three questions.
455×8 = 3640 ways to answer at least 12 questions on the quiz correctly.
That means there are 3640 ways to pass the quiz out of a total of 32768 ways to answer the questions, which leaves the student with a 3640/32768 = 0.11 = 11% chance to pass the test. This isn't likely to occur; it only happens around 1 in 10 times.