A spring gun at ground level fires a golf ball at an angle of 45 degrees. The ball lands 10 m away.

a) What was the ball's initial speed?

b) For the same initial speed, find the two firing angles that make the range 6 m.

Recall that the Ideal Projectile Motion Equation is

r=(vo*cos(theta))ti+((vo*sin(theta)t-1/2*g*t^2)j.

Answer: a) vo=sqrt(10g)

b) theta=1/2*arcsin(3/5),

theta=pi-1/2*arcsin(3/5).

And is arcsin the same thing as sin^-1?