The perimeter of a basketball court

Question

The perimeter of a basketball court is 282 ft. the length is 43 ft longer than the width. find the demensions of the court.
what is the length and what is the width?

Answer 1

Let l=length and w=width of basketball court

Lets convert these sentences into equations:

The perimeter of a basketball court is 282 ft, The perimeter of a rectangle is 2*l + 2*w

2l + 2w = 282

the length is 43 ft longer than the width

l=43+w

 

Start by substituting your equation for length into the first equation.

2l + 2w = 282

2(43+w) + 2w = 282

86 + 2w +2w = 282

4w = 196

w = 49

Then plug this value for w back into one of your original equations to solve for l.

l=43+w=43+49=92

 

w=49, l=92

 

hope this helps,

Chris