
Andrea O. answered 04/15/15
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To solve by eliminations you have to match the coefficient in equation 1 of either x or y with the coefficient of the 2nd equation of x or y.
(1)
6x-y=6
(2)
x+6y=38, I will multiply this equation by 6
6(x+6y = 38)
6x +36y = 228, now take this equation and subtract it from the first
6x-y=6 6
-(6x +36y = 228) ← If you don't see it, I'm just subtracting like I would whole number -(6)
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0x - 37y = -222 0
solve for y
y = 6 now you can plug this y into either equation (1) or (2) and solve for x
6x-6=6
6x = 12
x = 2
The answer is A. (2, 6)