Thomas C. answered 08/29/25
Physics PhD. Former Adjunct Professor
We know that 2.24 × 10-2 m3 of air at STP contains 6.022 × 1023 molecules.
The flask has a volume of 4.15 × 10-3 m3 and the air in it is at STP.
Since we have the number of molecules to volume at STP, we can set equal the ratios
(molecules in flask) / (4.15 × 10-3 m3) =( 6.022 × 1023 molecules) / (2.24 × 10-2 m3)
molecules in flask = ( 6.022 × 1023 molecules) × (4.15 × 10-3 m3)/(2.24 × 10-2 m3)
molecules in flask = ( 6.022 × 1023 molecules) × 0.185
molecules in flask = 1.114 × 1023 molecules