Edward C. answered 04/09/15
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Caltech Grad for math tutoring: Algebra through Calculus
Let X = width of the frame. The frame is on all 4 sides of the mirror (top and bottom, left and right) so the area of the mirror is
(14 - 2*X)*(20 - 2*X) = 160
280 - 40*X - 28*X + 4*X^2 = 160
4*X^2 - 68*X + 120 = 0
X - 17*X + 30 = 0
(X - 15)*(X - 2) = 0
X -15 = 0 or X - 2 = 0
X = 15 or X = 2
X = 15 will result in a negative mirror size so choose X = 2 in as the width of the frame
Check: (14 - 4)*(20 - 4) = 10*16 = 160 in^2 mirror