The length of a rectangular parking lot is twice the width. The area is 162 yd^2. Find the length and the width.

Question

The length of a rectangular parking lot is twice the width. The area is 162 yd^2. Find the length and the width.

Answer 1

Let width = x

Let length = 2x

Area = 162 yd²

 

length × width = Area

 

2x(x) = 162

2x² = 162

 

Divide by 2 on both sides of equation.

 

x² = 81

 

Square-root both sides of equation to undo the exponent.

 

x = √(81)

x = 9

 

Substitute this x value into the initial variables.

 

width = x = 9 yds

length = 2x = 2(9) = 18 yds