In 2011 city of Chicago’s population was 2.71 million people, which was 6.5% less than what it was in 2000. What was the population of Chicago in 2000

Question

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Answer 1

Answer: 2.89

 

The 2011 population of 2.71 million is 93.5% of the 2000 population, which will be 100%.

 

Step 1: Write 2.71/x = 93.5/100

Step 2: Cross multiply to get 271 = 93.5x

Step 3: Divide 271 by 93.5 to get x, which is 2.89.

Answer 2

100%=x people in 2000

100-6.5=93.5%=2710000

 

100= x

----      ----

93.5  2710000

 

100*2710000=93.5x

 

x=271000000/93.5

x=2,898,395.72 people in 2000 or 2.90m 

 

 

Answer 3

100% - 6.5% = 93.5%

2.71 / 0.935 = 2.8983

 

So Chicago had about 2.90 million people, rounded to the nearest hundredth.

Answer 4

James, let's call the 2000 population p.  If we take 6.5% off of something, then we have 100% - 6.5% = 93.5%.  93.5% = .935

 

.935p = 2.71 million

 

Dividing both sides by .935, we get p = 2.9 million.

 

Let's check.  2.9 x .065 = .19

 

2.9 million - .19 million = 2.71 million.  Check!